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I've noticed some trends among people that avatarfag with Lucky Star characters. People with certain personality/behavioral traits tend to gravitate towards certain characters. This is what I have observed.

Konatafags:
-The most common type of LS avatarfag
-Generally male, predominantly heterosexual
-Very low intelligence
-Is a pedophile
-Poor hygiene and living conditions
-NEET, hikikomori or freeter
-Either underweight or obese

Tsukasafags:
-Male, predominantly homosexual (but may hide this fact)
-Submissive bottoms
-Enjoy crossdressing
-Shy
-Very intelligent, but don't make it a point of pride or let it go to their head
-Often struggle with issues such as anxiety, depression, OCD and autism

Kagamifags:
-Predominantly female
-Lesbian
-A little stuck up
-Always gets their way, often coming off as pushy or rude

Miyukifags:
-Rarest LS avatarfag
-May be male or female
-Mature and grounded
-Trustworthy
-Good listeners
-Gentle and kind

Yutaka and Akirafags:
-Chronically silly
-Can't take anything seriously
-Was probably molested as a child
-Reliant upon humor to cope with suffering
Marked for deletion (Old)
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Hey, I am NOT of low intelligence!
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:D
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>>136602
Okay, guess you'll have no problem with this then. nyaoo

x²−61y²=1

Solve the Diophantine equation for positive integers x and y.
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>-Male, predominantly homosexual
>-Submissive bottoms
>-Enjoy crossdressing
So true bestie💘blush
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>-Is a pedophile
So true bestie💘nyaoo-closedeyes
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Spot on!
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キタ━━━(゚∀゚)━━━!!
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x²−61y²=1
x²=1+61y²
x=(1+61y²)/x

-61y²=1-x²
-y²=(1-x²)/61
-y=((1-x²)/61)/y
y=(((1-x²)/61)/y)*-1
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>>136614
i think he was asking for the proper x and y so that x^2 - ny^2 = 1, not to simplify it

>>136604
you use the structure x^2-ny^2 = 1, so this is pell's equation

x^2 - ny^2 = 1 where n = 61

we have to find the continued fraction of n, 61
sqrt(61) = 7.8102, but we'll round down to represent it as 7. but in memory keep the decimal to about 4 points, we'll use it later. we will create a set that we'll use to compute the converging points, P.
P = {7}

from there bring back the 7.8102 and subtract the 7 for 0.8102, divide 1 by that and you'll get 1.2342, rounding down for 1 so add that to the set
P = {7, 1}
bring back 1.2342 and do the same thing as we did for 7

we're gonna repeat this process a bunch until we end up with
{7, 1, 4, 3, 1, 2, 2, 1, 3, 4, 1, 14...} we'll stop there

now lets get the convergents
we'll use Cq = xq/yq

the initial value of h is our first element and the denominator initializes to 1
x0 = 7
y0 = 1

so C0 = 7 / 1

before we move further let's bring back the original equation and try plugging shit in
(x0)^2 - 61(y0)^2 = (7)^2 - 61(1)^2 = 49 - 3721 = -3672 which =/= 1, which isn't what we're
looking for so this can't be it. lets continue the process

for the x1 and y1 values i'll use these equations
x1 = a0 * x1 + 1
y1 = a1

x1 = 1 * 7 + 1 = 8
y1 = 1 * 1 = 1

C1 = 8 / 1

lets try again

(x1)^2 - 61(y1)^2 = (8)^2 - 61(1)^2 = 64 - 3721 = -3657 =/= 1
nope

for anything greater than that i'll use this
xq = aqx(q-1) + x(q-2)
yq = aqy(q-1) + y(q-2)

so x2 = 1 * 8 + 7 = 15
y2 = 1* 1 + 1 = 2

C2 = 15 / 2

i dont want to write it down but this doesnt work either

and so on and so on. now we just keep repeating this process until we find a number that works, which isnt for a retardedly long time
it is so long we dont get to it until about the 19th convergent, of which the numbers are

C19 = 1766319049 / 226153980

lets try it to confirm

(1766319049)^2 - 61(226153980)^2 = 3119882982860264401 - 3119882982860264400 = 1

yay! x^2 - 61y^2 = 1! this intentionally obtuse equation is solved
alternatively you could plug the equation into desmos or look at the pell's equation wikipedia page
sry i did not use proper ascii notation i could not be fucked
much fun to be had on heyuri.net the place to be
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wow people who like konata are really smart dizzy
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>>136617
paedo == high iq wink
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>paedo == high iq
since they are able to solve such complex math equations like that then it has to be true biggrin
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>>136620
and they get to fly on cool planes like the epstein express and be billionaires and royalty and shit
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>>136622
not only smart but rich and famous. i have a new respect for pedophiles.
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Nekonata! nyaoo-closedeyes
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i failed... nyaoo2
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Konyata nyaoo-closedeyes
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it is incorrect about akirafags!
i was not molested in childhood!
i was the molester (´ー`)
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Remove Kagami from this picture immediately...
And Akira is the cutest idol, nobody has a right to insult her crowds...

Kay?
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my favorite character goes unnoticed nyaoo-closedeyes
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>Remove Kagami from this picture immediately...
CONSIDER IT DONE
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...uh oh


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