[Settings] [Home] [Catalog] [Search] [Private messages] [Admin]
[Return] [Bottom]

Posting mode: Reply

Emotes
Kaomoji
Emoji
BBCode
(for deletion)
  • Allowed file types are: gif, jpg, jpeg, png, bmp, swf, webm, mp4
  • Maximum file size allowed is 50000 KB.
  • Images greater than 200 * 200 pixels will be thumbnailed.
  • 24 unique users in the last 10 minutes (including lurkers)





Want your banner here? Click here to submit yours!

I've noticed some trends among people that avatarfag with Lucky Star characters. People with certain personality/behavioral traits tend to gravitate towards certain characters. This is what I have observed.

Konatafags:
-The most common type of LS avatarfag
-Generally male, predominantly heterosexual
-Very low intelligence
-Is a pedophile
-Poor hygiene and living conditions
-NEET, hikikomori or freeter
-Either underweight or obese

Tsukasafags:
-Male, predominantly homosexual (but may hide this fact)
-Submissive bottoms
-Enjoy crossdressing
-Shy
-Very intelligent, but don't make it a point of pride or let it go to their head
-Often struggle with issues such as anxiety, depression, OCD and autism

Kagamifags:
-Predominantly female
-Lesbian
-A little stuck up
-Always gets their way, often coming off as pushy or rude

Miyukifags:
-Rarest LS avatarfag
-May be male or female
-Mature and grounded
-Trustworthy
-Good listeners
-Gentle and kind

Yutaka and Akirafags:
-Chronically silly
-Can't take anything seriously
-Was probably molested as a child
-Reliant upon humor to cope with suffering
Marked for deletion (Old)
>>
Hey, I am NOT of low intelligence!
>>
File: 009.jpg
[Spoiler](72 KB, 500x500)
73728
:D
>>
>>136602
Okay, guess you'll have no problem with this then. nyaoo

x²−61y²=1

Solve the Diophantine equation for positive integers x and y.
>>
File: mebasically.jpg
[Spoiler](138 KB, 414x832)
141312
>-Male, predominantly homosexual
>-Submissive bottoms
>-Enjoy crossdressing
So true bestie💘blush
>>
File: mebasically.png
[Spoiler](149 KB, 314x437)
152576
>-Is a pedophile
So true bestie💘nyaoo-closedeyes
>>
697344
Spot on!
>>
File: konabliss.jpg
[Spoiler](383 KB, 1024x768)
392192
キタ━━━(゚∀゚)━━━!!
>>
x²−61y²=1
x²=1+61y²
x=(1+61y²)/x

-61y²=1-x²
-y²=(1-x²)/61
-y=((1-x²)/61)/y
y=(((1-x²)/61)/y)*-1
>>
File: sweaty penis.jpg
[Spoiler](623 KB, 1008x914)
637952
>>136614
i think he was asking for the proper x and y so that x^2 - ny^2 = 1, not to simplify it

>>136604
you use the structure x^2-ny^2 = 1, so this is pell's equation

x^2 - ny^2 = 1 where n = 61

we have to find the continued fraction of n, 61
sqrt(61) = 7.8102, but we'll round down to represent it as 7. but in memory keep the decimal to about 4 points, we'll use it later. we will create a set that we'll use to compute the converging points, P.
P = {7}

from there bring back the 7.8102 and subtract the 7 for 0.8102, divide 1 by that and you'll get 1.2342, rounding down for 1 so add that to the set
P = {7, 1}
bring back 1.2342 and do the same thing as we did for 7

we're gonna repeat this process a bunch until we end up with
{7, 1, 4, 3, 1, 2, 2, 1, 3, 4, 1, 14...} we'll stop there

now lets get the convergents
we'll use Cq = xq/yq

the initial value of h is our first element and the denominator initializes to 1
x0 = 7
y0 = 1

so C0 = 7 / 1

before we move further let's bring back the original equation and try plugging shit in
(x0)^2 - 61(y0)^2 = (7)^2 - 61(1)^2 = 49 - 3721 = -3672 which =/= 1, which isn't what we're
looking for so this can't be it. lets continue the process

for the x1 and y1 values i'll use these equations
x1 = a0 * x1 + 1
y1 = a1

x1 = 1 * 7 + 1 = 8
y1 = 1 * 1 = 1

C1 = 8 / 1

lets try again

(x1)^2 - 61(y1)^2 = (8)^2 - 61(1)^2 = 64 - 3721 = -3657 =/= 1
nope

for anything greater than that i'll use this
xq = aqx(q-1) + x(q-2)
yq = aqy(q-1) + y(q-2)

so x2 = 1 * 8 + 7 = 15
y2 = 1* 1 + 1 = 2

C2 = 15 / 2

i dont want to write it down but this doesnt work either

and so on and so on. now we just keep repeating this process until we find a number that works, which isnt for a retardedly long time
it is so long we dont get to it until about the 19th convergent, of which the numbers are

C19 = 1766319049 / 226153980

lets try it to confirm

(1766319049)^2 - 61(226153980)^2 = 3119882982860264401 - 3119882982860264400 = 1

yay! x^2 - 61y^2 = 1! this intentionally obtuse equation is solved
alternatively you could plug the equation into desmos or look at the pell's equation wikipedia page
sry i did not use proper ascii notation i could not be fucked
much fun to be had on heyuri.net the place to be
>>
wow people who like konata are really smart dizzy
>>
>>136617
paedo == high iq wink
>>
>paedo == high iq
since they are able to solve such complex math equations like that then it has to be true biggrin
>>
>>136620
and they get to fly on cool planes like the epstein express and be billionaires and royalty and shit
>>
>>136622
not only smart but rich and famous. i have a new respect for pedophiles.
>>
File: Nekonata.jpg
[Spoiler](553 KB, 987x1340)
566272
Nekonata! nyaoo-closedeyes
>>
File: nekonata-2.gif
[Animated GIF][Spoiler](7 KB, 200x200)
7168
i failed... nyaoo2
>>
Konyata nyaoo-closedeyes
>>
it is incorrect about akirafags!
i was not molested in childhood!
i was the molester (´ー`)
>>
File: p.png
[Spoiler](598 KB, 1280x720)
612352
Remove Kagami from this picture immediately...
And Akira is the cutest idol, nobody has a right to insult her crowds...

Kay?
>>
436224
my favorite character goes unnoticed nyaoo-closedeyes
>>
File: removed.jpg
[Spoiler](2.17 MB, 2048x1096)
2273280
>Remove Kagami from this picture immediately...
CONSIDER IT DONE
>>
...uh oh

Want your banner here? Click here to submit yours!

[Top]

Delete post: []
First
[1]
Last